Question #259651

Q5.Cheak if ϕ = X2– Y2+ Y represents the velocity potential for 2 dimensional




Irrotational flow. If it does than determine than determine stream function Ψ.

1
Expert's answer
2021-11-01T19:22:45-0400

The condition for irrotational motion


uyvx=0\dfrac{\partial u}{\partial y}-\dfrac{\partial v}{\partial x}=0

From the definition of stream function ψ,ψ , we get u=ϕx,v=ϕyu =\dfrac{\partial \phi}{\partial x}, v=\dfrac{\partial\phi}{\partial y}

Thus, the velocity components become


u=ϕx=2x,v=ϕy=2y+1u =\dfrac{\partial \phi}{\partial x}=2x, v=\dfrac{\partial\phi}{\partial y}=-2y+1

uy=0,vx=0\dfrac{\partial u}{\partial y}=0, \dfrac{\partial v}{\partial x}=0


Since

uyvx=00=0\dfrac{\partial u}{\partial y}-\dfrac{\partial v}{\partial x}=0-0=0

then  ϕ=x2y2+yϕ = x^2– y^2+y represents the velocity potential for 2 dimensional Irrotational flow.



ψy=u=2x,ψx=v=2y+1\dfrac{\partial \psi}{\partial y}=u=2x, -\dfrac{\partial \psi}{\partial x}=v=-2y+1

Then


ψ=2xy+g(x)\psi=2xy+g(x)

ψx=2y+g(x)=v=2y1\dfrac{\partial \psi}{\partial x}=2y+g'(x)=-v=2y-1

g(x)=1g'(x)=-1

g(x)=x+Cg(x)=-x+C

Stream function is


ψ=2xyx+C\psi=2xy-x+C


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