In velocity we can write
u=∂y∂ψ,v=−∂x∂ψGiven ψ=2x−5y
u=∂y∂ψ=−5,v=−∂x∂ψ=−2u=−5,v=−2∣velocity∣=u2+v2=(−5)2+(−2)2=29tanθ=uv=−5−2=0.4The vector of the resultant velocity at any point consists the angle tan−1(0.4)≈21.8° with the positive direction of the x-axis.
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