Question #259650

A stream function is given by Ψ = 2x- 5y. Calculate the velocity components




and also magnitude and direction of the resultant velocity at any point

1
Expert's answer
2022-08-10T16:04:07-0400

In velocity we can write


u=ψy,v=ψxu=\dfrac{\partial\psi}{\partial y}, v=-\dfrac{\partial\psi}{\partial x}

Given ψ=2x5y\psi=2x-5y

u=ψy=5,v=ψx=2u=\dfrac{\partial\psi}{\partial y}=-5, v=-\dfrac{\partial\psi}{\partial x}=-2u=5,v=2u=-5, v=-2velocity=u2+v2=(5)2+(2)2=29|velocity|=\sqrt{u^2+v^2 }=\sqrt{(-5)^2+(-2)^2}=\sqrt{29}tanθ=vu=25=0.4\tan\theta=\dfrac{v}{u}=\dfrac{-2}{-5}=0.4

The vector of the resultant velocity at any point consists the angle tan1(0.4)21.8°\tan^{-1}(0.4)\approx21.8\degree with the positive direction of the x-axis.


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