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Question #241814
The 80th term of fibonacii sequence is?
Expert's answer
Use Binet formula
F
n
=
α
n
−
β
n
α
−
β
F_n=\dfrac{\alpha^n-\beta^n}{\alpha-\beta}
F
n
=
α
−
β
α
n
−
β
n
α
=
1
+
5
2
,
β
=
1
−
5
2
\alpha=\dfrac{1+\sqrt{5}}{2}, \beta=\dfrac{1-\sqrt{5}}{2}
α
=
2
1
+
5
,
β
=
2
1
−
5
α
−
β
=
5
\alpha-\beta=\sqrt{5}
α
−
β
=
5
F
80
=
(
1
+
5
)
80
−
(
1
−
5
)
80
2
80
5
F_{80}=\dfrac{(1+\sqrt{5})^{80}-(1-\sqrt{5})^{80}}{2^{80}\sqrt{5}}
F
80
=
2
80
5
(
1
+
5
)
80
−
(
1
−
5
)
80
F
80
=
14472334024676221
F_{80}= 14472334024676221
F
80
=
14472334024676221
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on Dec 2023
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