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Question #241813
Solve for the 67th term of the fibonacci sequence?
Expert's answer
Use Binet formula
F
n
=
α
n
−
β
n
α
−
β
F_n=\dfrac{\alpha^n-\beta^n}{\alpha-\beta}
F
n
=
α
−
β
α
n
−
β
n
α
=
1
+
5
2
,
β
=
1
−
5
2
\alpha=\dfrac{1+\sqrt{5}}{2}, \beta=\dfrac{1-\sqrt{5}}{2}
α
=
2
1
+
5
,
β
=
2
1
−
5
α
−
β
=
5
\alpha-\beta=\sqrt{5}
α
−
β
=
5
F
67
=
(
1
+
5
)
67
−
(
1
−
5
)
67
2
67
5
F_{67}=\dfrac{(1+\sqrt{5})^{67}-(1-\sqrt{5})^{67}}{2^{67}\sqrt{5}}
F
67
=
2
67
5
(
1
+
5
)
67
−
(
1
−
5
)
67
F
67
=
27777890035288
F_{67}=27777890035288
F
67
=
27777890035288
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