Question #241813

Solve for the 67th term of the fibonacci sequence?


1
Expert's answer
2021-09-27T14:13:20-0400

Use Binet formula


Fn=αnβnαβF_n=\dfrac{\alpha^n-\beta^n}{\alpha-\beta}

α=1+52,β=152\alpha=\dfrac{1+\sqrt{5}}{2}, \beta=\dfrac{1-\sqrt{5}}{2}

αβ=5\alpha-\beta=\sqrt{5}

F67=(1+5)67(15)672675F_{67}=\dfrac{(1+\sqrt{5})^{67}-(1-\sqrt{5})^{67}}{2^{67}\sqrt{5}}

F67=27777890035288F_{67}=27777890035288


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