Answer to Question #201571 in Math for rama

Question

In a chemical reaction of Propane and oxygen gives the carbon dioxide and water as

given below

C3H3 + O2 -! CO2 + H2O

Using Gauss Seidel method Find the numbers of atoms of C, H, O.

Answer 1

Write the unbalanced combustion reaction as follows

$$C_3H_3(g)+O_2(g)\to CO_2(g)+H_2O (g)$$

Balance the equation as follows

Consider $H$

The least common multiplier of $3$ in left side and $2$ in right side is $6.$ Then

$$2C_3H_3(g)+O_2(g)\to CO_2(g)+3H_2O (g)$$

Consider $C$

The least common multiplier of $2(3)$ in left side and $1$ in right side is $6.$ Then

$$2C_3H_3(g)+O_2(g)\to 6CO_2(g)+3H_2O (g)$$

Check $O$

We have even number of atoms of $O$ in left side and odd number of atoms of $O$ in right side. Multiple both sides by $2$

$$4C_3H_3(g)+2O_2(g)\to 12CO_2(g)+6H_2O (g)$$

We have $2$ atoms of $O$ in left side and $12(2)+6=30$ atoms of $O$ in right side. Then

$$4C_3H_3(g)+15O_2(g)= 12CO_2(g)+6H_2O (g)$$

12 atoms of $C$

12 atoms of $H$

30 atoms of $O$