Answer to Question #201035 in Math for aziilah

Question

Supposed a 70 kg man climbs up a mountain as shown in the figure below.

Determine the work done to climb the mountain from the bottom of the mountain to the

location marked with an orange circle at 100 m height. ( x-axis = 20m, y-axis = 100m)

Approach the problem using vector analysis

Answer 1

$$W=\Delta U=mg\Delta h$$

Given

$m=70\ kg$

$g=9.81 \ m/s^2$

$\Delta h=100\ m-0\ m=100\ m$

$$W=\Delta U=70kg(9.81m/s^2)(100m)=68670\ J$$

The work done is $68670\ J.$