Question #237070

) Find the dual program of the following linear programming problem.

𝑀𝑖𝑛𝑖𝑚𝑖𝑧𝑒 𝑃 = 16𝑥 − 2𝑦 − 5𝑧

𝑠𝑢𝑏𝑗𝑒𝑐𝑡 𝑡𝑜

𝑥 + 4𝑦 − 𝑧 ≥ 120

𝑥 + 𝑦 + 3𝑧 ≤ 130

𝑥 ≥ 0, 𝑦 ≥ 0, 𝑧 𝑖𝑠 𝑢𝑛𝑟𝑒𝑠𝑡𝑟𝑖𝑐𝑡𝑒𝑑.


1
Expert's answer
2021-09-28T01:16:40-0400

All constraints can be converted to \geq  by multiplying by -1. So we have;

Min  p=16x2y5zsubject to     x+4yz120 x  y+3z130and x,y0;zis unrestricted.\text{Min} ~~p=16x-2y-5z\\ \text{subject to}\\ ~~~~~x+4y-z\geq120\\ ~-x-~~y+3z\geq-130\\ \text{and } x,y\geq 0; z \text{is unrestricted}.

Since the primal has three variables and two constraints, then the dual will have two variables and three constraints. Also, the zz variable is unrestricted in the primal, therefore the third constraint in the dual shall be equality.

Dual program is;

Max   p=1220a130bsubject to      ab   16       4ab   2     a3b =5and a,b0.\text{Max } ~~p=1220a-130b\\ \text{subject to }\\ ~~~~~-a-b~~~\leq16\\ ~~~~~~~4a-b~~~\leq-2\\ ~~~~~-a-3b~=-5\\ \text{and } a,b\geq0.

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