Question #237068

Find the dual program of the following linear programming problem.

š‘€š‘Žš‘„š‘–š‘šš‘–š‘§š‘’ š‘§ = 5š‘„1 āˆ’ 2š‘„2

š‘ š‘¢š‘š‘—š‘’š‘š‘” š‘”š‘œ

3š‘„1 + 2š‘„2 ≄ 16

š‘„1 āˆ’ š‘„2 ≤ 4

š‘„1 ≄ 5

š‘„1 ≄0,š‘„2 š‘–š‘  š‘¢š‘›š‘š‘œš‘›š‘ š‘”š‘Ÿš‘Žš‘–š‘›š‘’š‘‘ 


Expert's answer

All constraints can be converted to ≤\leq by multiplying by -1. So we have;

Max  z=5x1āˆ’2x2subject to     āˆ’3x1āˆ’2x2ā‰¤āˆ’16           x1āˆ’  x2≤4       āˆ’x1           ā‰¤āˆ’5and x1≤0;x2is unrestricted.\text{Max} ~~z=5x_1-2x_2\\ \text{subject to}\\ ~~~~~-3x_1-2x_2\leq-16\\ ~~~~~~~~~~~x_1-~~x_2\leq4\\ ~~~~~~~-x_1~~~~~~~~~~~\leq-5\\ \text{and } x_1\leq 0; x_2 \text{is unrestricted}.

Since the primal has two variables and three constraints, then the dual will have three variables and two constraints. Also, the x2x_2 variable is unrestricted in the primal, therefore the second constraint in the dual shall be equality.

Dual program is;

Min   z=āˆ’16y1+4y2āˆ’5y3subject to      āˆ’3y1+y2āˆ’y3≄5     āˆ’2y1āˆ’y2        =āˆ’2and y1,y2≄0.\text{Min } ~~z=-16y_1+4y_2-5y_3\\ \text{subject to }\\ ~~~~~-3y_1+y_2-y_3\geq5\\ ~~~~~-2y_1-y_2~~~~~~~~=-2\\ \text{and } y_1,y_2\geq0.



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