Question #81384

which of the following statements are true and which are false ? justify your answer with a short proof or a counterexample. i) r^2 has infinitely many non zero, proper vector subspaces. ii) if t:v -> w is one-one linear transformation between two finite dimensional vector spaces v and w then t is invertible. iii) if a^k = 0 for a square matrix a, then all the eigen values of a are non zero. iv) every unitary operator is invertible. v) every system of homogeneous linear equations has a non zero solution.
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Expert's answer

2018-09-26T10:37:08-0400

Answer on Question #81384 – Math – Linear Algebra

which of the following statements are true and which are false? justify your answer with a short proof or a counterexample.

Question

(i) R2\mathbb{R}^2 has infinitely many nonzero, proper vector subspaces

Solution

Let {e1,e2}\{e_1, e_2\} be a basis in R2\mathbb{R}^2. Then


Wn={α(e1+ne2),αR},nNW_n = \{\alpha(e_1 + ne_2), \alpha \in \mathbb{R}\}, n \in \mathbb{N}


are all different proper vector subspaces. Indeed, suppose Wn=WmW_n = W_m. Then


e1+ne2=α(e1+me2)e_1 + ne_2 = \alpha(e_1 + me_2)


for some α\alpha.

Then


(α1)e1+(mαn)e2=0(\alpha - 1)e_1 + (m\alpha - n)e_2 = 0


from which α=1,α=n/m\alpha = 1, \alpha = n/m, i.e. n=mn = m.

This proves that WnW_n are all different. And there are infinitely many of them.

Conclusion: R2\mathbb{R}^2 has infinitely many nonzero, proper vector subspaces – true.

Question

ii) if T:VWT: V \to W is one-one linear transformation between two finite dimensional vector spaces VV and WW then TT is invertible

Solution

Let TT be one-to-one. For any yWy \in W define SySy as the (unique) solution to Tx=yTx = y.

Then obviously


S(Tx)=x.S(Tx) = x.


It is sufficient to prove that SS is linear.


S(α1y1+α2y2)=α1Sy1+α2Sy2S(\alpha_1y_1 + \alpha_2y_2) = \alpha_1Sy_1 + \alpha_2Sy_2


Let Sy1=x1,Sy2=x2Sy_1 = x_1, Sy_2 = x_2. Then


T(α1x1+α2x2)=T(α1Sy1+α2Sy2)=α1T(Sy1)+α2T(Sy2)=α1y1+α2y2,T(\alpha_1x_1 + \alpha_2x_2) = T(\alpha_1Sy_1 + \alpha_2Sy_2) = \alpha_1T(Sy_1) + \alpha_2T(Sy_2) = \alpha_1y_1 + \alpha_2y_2,


from which


α1x1+α2x2=S(α1y1+α2y2)\alpha_1 x_1 + \alpha_2 x_2 = S(\alpha_1 y_1 + \alpha_2 y_2)


which proves linearity.

Conclusion: if T:VWT: V \to W is one-one linear transformation between two finite dimensional vector spaces VV and WW then TT is invertible - true.

Question

iii) if Akk=0A^k k = 0 for a square matrix AA, then all the eigen values of aa are nonzero

Solution

Consider A=0A = 0. It has all zero eigenvalues.

Conclusion: if Akk=0A^k k = 0 for a square matrix AA, then all the eigen values of aa are nonzero - false.

Question

iv) every unitary operator is invertible

Solution

By definition an unitary operator UU is such that


UU=UU,U U^* = U^* U,


thus UU^* is inverse of UU.

Conclusion: every unitary operator is invertible - true.

Question

v) every system of homogeneous linear equations has a nonzero solution

Solution

Consider a system:


{x1+x2=0x1x2=0\left\{ \begin{array}{l} x_1 + x_2 = 0 \\ x_1 - x_2 = 0 \end{array} \right.


It has only zero solution.

Conclusion: every system of homogeneous linear equations has a nonzero solution - false.

Answer:

(i) R2\mathbb{R}^2 has infinitely many non-zero, proper vector subspaces - true;

ii) if T:VWT: V \to W is one-one linear transformation between two finite dimensional vector spaces

V and W then T is invertible – true;

iii) if Ak=0A^k = 0 for a square matrix A, then all the eigen values of a are nonzero – false;

iv) every unitary operator is invertible – true;

v) every system of homogeneous linear equations has a nonzero solution – false.

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