Question #81142

Complete the set S = {x
3 +x
2 +1, x
2 +x+1, x+1} to get a basis of P3

Expert's answer

Answer on Question #81142 – Math – Linear Algebra

Question

Complete the set S={xS = \{x

3 + x

2 + 1, x

2 + x + 1, x + 1 \} to get a basis of P3

Solution

Denote


a1=x3+x2+1,a2=x2+x+1,a3=x+1.a_1 = x^3 + x^2 + 1, a_2 = x^2 + x + 1, a_3 = x + 1.


Let's check the hypothesis that a1,a2,a3a_1, a_2, a_3 and a4=1a_4 = 1 form a basis in P3P_3. We have to check whether c1a1+c2a2+c3a3+c4a4=0c_1a_1 + c_2a_2 + c_3a_3 + c_4a_4 = 0

yields


c1=c2=c3=c4=0.c_1 = c_2 = c_3 = c_4 = 0.


We have


c1(x3+x2+1)+c2(x2+x+1)+c3(x+1)+c41=0c_1(x^3 + x^2 + 1) + c_2(x^2 + x + 1) + c_3(x + 1) + c_4 \cdot 1 = 0


This means


c1x3+(c1+c2)x2+(c2+c3)x+(c1+c2+c3+c4)=0.c_1x^3 + (c_1 + c_2)x^2 + (c_2 + c_3)x + (c_1 + c_2 + c_3 + c_4) = 0.


Then


{c1=0c1+c2=0c2+c3=0c1+c2+c3+c4=0\left\{ \begin{array}{l} c_1 = 0 \\ c_1 + c_2 = 0 \\ c_2 + c_3 = 0 \\ c_1 + c_2 + c_3 + c_4 = 0 \end{array} \right.


from which


c1=0,c2=c1=0,c3=c2=0,c4=c1c2c3=0.c_1 = 0, c_2 = -c_1 = 0, c_3 = -c_2 = 0, c_4 = -c_1 - c_2 - c_3 = 0.


This means that a1,a2,a3,a4a_1, a_2, a_3, a_4 really form a basis in P3P_3.

Answer: 1 should be added, the basis of P3P_3 is {x3+x2+1,x2+x+1,x+1,1}\{x^3 + x^2 + 1, x^2 + x + 1, x + 1, 1\}.

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