Answer to Question #350832 in Linear Algebra for Busi

Question #350832

The following were obtained by applying Kirchoff’s laws to an electric circuit


2IA +IB −IC = −8


−IA +IB +IC = 3


−2IA +4IC = 18


1
Expert's answer
2022-06-16T09:49:51-0400

Augmented matrix


"\\begin{pmatrix}\n 2 & 1 & -1 & & -8 \\\\\n -1 & 1 & 1 & & 3 \\\\\n -2 & 0 & 4 & & 18 \\\\\n\\end{pmatrix}"

"R_1=R_1\/2"


"\\begin{pmatrix}\n 1 & 1\/2 & -1\/2 & & -4 \\\\\n -1 & 1 & 1 & & 3 \\\\\n -2 & 0 & 4 & & 18 \\\\\n\\end{pmatrix}"

"R_2=R_2+R_1"


"\\begin{pmatrix}\n 1 & 1\/2 & -1\/2 & & -4 \\\\\n0 & 3\/2 & 1\/2 & & -1 \\\\\n -2 & 0 & 4 & & 18 \\\\\n\\end{pmatrix}"

"R_3=R_3+2R_1"


"\\begin{pmatrix}\n 1 & 1\/2 & -1\/2 & & -4 \\\\\n0 & 3\/2 & 1\/2 & & -1 \\\\\n 0 & 1 & 3 & & 10 \\\\\n\\end{pmatrix}"

"R_2=2R_2\/3"


"\\begin{pmatrix}\n 1 & 1\/2 & -1\/2 & & -4 \\\\\n0 & 1 & 1\/3 & & -2\/3 \\\\\n 0 & 1 & 3 & & 10 \\\\\n\\end{pmatrix}"

"R_1=R_1-R_2\/2"


"\\begin{pmatrix}\n 1 & 0 & -2\/3 & & -11\/3 \\\\\n0 & 1 & 1\/3 & & -2\/3 \\\\\n 0 & 1 & 3 & & 10 \\\\\n\\end{pmatrix}"

"R_3=R_3-R_2"


"\\begin{pmatrix}\n 1 & 0 & -2\/3 & & -11\/3 \\\\\n0 & 1 & 1\/3 & & -2\/3 \\\\\n 0 & 0 & 8\/3 & & 32\/3 \\\\\n\\end{pmatrix}"

"R_3=3R_3\/8"


"\\begin{pmatrix}\n 1 & 0 & -2\/3 & & -11\/3 \\\\\n0 & 1 & 1\/3 & & -2\/3 \\\\\n 0 & 0 & 1 & & 4 \\\\\n\\end{pmatrix}"

"R_1=R_1+2R_3\/3"


"\\begin{pmatrix}\n 1 & 0 & 0 & & -1 \\\\\n0 & 1 & 1\/3 & & -2\/3 \\\\\n 0 & 0 & 1 & & 4 \\\\\n\\end{pmatrix}"

"R_2=R_2-R_3\/3"


"\\begin{pmatrix}\n 1 & 0 & 0 & & -1 \\\\\n0 & 1 & 0 & & -2\\\\\n 0 & 0 & 1 & & 4 \\\\\n\\end{pmatrix}"

"I_A=-1, I_B=-2, I_C=4"

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS