Let
A=[acbd] Then
A2=[acbd][acbd]=[a2+bcac+dcab+bdbc+d2] Given A2 is a diagonal. Then
{ab+bd=0ac+dc=0=>{b(a+d)=0c(a+d)=0 If a+d=0, then b=c=0, and matrix A=[a00d] is a diagonal.
We have contradiction.
Hence a+d=0 and at least one of the numbers c and b is not equal to zero.
Therefore
A=[acb−a], and at least one of the numbers c and b is not equal to zero.
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