Let us determine wheather the set W={(a,b,c):a2+b2+c2≤1,a,b,c∈R} is a subspace of R3. Taking into account that 12+02+02=1≤1, we conclude that (1,0,0)∈W. On the other hand, (1,0,0)+(1,0,0)=(2,0,0)∈/W because 22+02+02=4>1. Therefore, W is not a subspace of R3.
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