Question #282359

Suppose U and V are subspace of R^n. Prove that orthogonal of ( U intersection V)=orthogonal of U+ orthogonal of V

Expert's answer

for u,v∈U∩Vu,v\isin U\cap V :

if x∈(U∩V)⊥x\isin (U\cap V)^{\perp} and U∩V≠0U\cap V \neq 0 then:

x⋅u=0x\cdot u=0 or x⋅v=0x\cdot v=0 , so

x∈U⊥+V⊥x\isin U^{\perp}+V^{\perp}

so,

(U∩V)⊥(U\cap V)^{\perp} is subset of U⊥+V⊥U^{\perp}+V^{\perp}


if x∈U⊥+V⊥x\isin U^{\perp}+V^{\perp} then:

x⋅u=0x\cdot u=0 or x⋅v=0x\cdot v=0 for u∈Uu\isin U and v∈Vv\isin V

then x∈(U∩V)⊥x\isin (U\cap V)^{\perp}

so,

U⊥+V⊥U^{\perp}+V^{\perp} is subset of (U∩V)⊥(U\cap V)^{\perp}


that is, (U∩V)⊥=U⊥+V⊥(U\cap V)^{\perp} =U^{\perp}+V^{\perp}


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