Suppose u, v is the element of V and || u || = || v || = 1 with < u,v > = 1: Prove
that u = v.
It follows that "\\cos \\alpha=\\frac{<u,v>}{||u||\\cdot ||v||}=\\frac{1}{1}=1," and hence "\\alpha =0." Since the vectors "u" and "v" have the same direction and the same magnitude, we conclude that "u=v."
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