Suppose T L(V) is invertible.
(a) Suppose F with not= 0. Prove that is an eigenvalue of T if and only if 1/ is an eigenvalue of T-1.
(b) Prove that T and T-1 have the same eigenvectors.
(a)
is an eigenvalue of
there exists a nonzero such that
there exists a nonzero such that
there exists a nonzero such that
there exists a nonzero such that
is an eigenvalue of
(b)
Note that since is invertible, is injective.
Suppose is an eigencouple of Then ; thus and in fact there cannot be any eigenvectors of corresponding to
Now, suppose is an eigenvector of corresponding to
By the proof of (a), is an eigenvector of corresponding to
So all eigenvectors of are eigenvectors of ; reversing the roles of and yields the reverse inclusion and completes the proof.
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