Suppose T 2 L(R2) is deÖned by T(x; y) = ((3y; x). Find the eigenvalues of T
Let 𝜆 be an eigenvalue of 𝑇. It means that T(x,y)=λ(x,y)T(x,y)=\lambda(x,y)T(x,y)=λ(x,y)
(3y,x)=λ(x,y)(3y,x)=\lambda (x,y)(3y,x)=λ(x,y)
x=λyx=\lambda yx=λy and 3y=λx=λ2y3y=\lambda x=\lambda ^2y3y=λx=λ2y
We obtain λ2=3, λ=±3\lambda ^2=3,\ \ \ \ \lambda =\pm \sqrt{3}λ2=3, λ=±3
Answer: λ=±3\lambda=\pm \sqrt{3}λ=±3 .
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