⎝⎛4126−1−563−2⎠⎞Start from forming a new matrix by subtracting λ from the diagonal entries of the given matrix:
⎝⎛4−λ126−1−λ−563−2−λ⎠⎞
∣∣4−λ126−1−λ−563−2−λ∣∣
=(4−λ)∣∣−1−λ−53−2−λ∣∣−6∣∣123−2−λ∣∣
+6∣∣12−1−λ−5∣∣
=(4−λ)(1+λ)(2+λ()+15(4−λ)
+6(2+λ)+36−30+12(1+λ)
=8+12λ+4λ2−2λ−3λ2−λ3+60−15λ
+12+6λ+6+12+12λ
=−λ3+λ2+13λ+98 Solve the equation
−λ3+λ2+13λ+98=0Only approximate roots can be found.
The roots are
λ1≈5.9513233156912
λ2≈−2.4756616578456+3.21527996418223i
λ3≈−2.4756616578456−3.21527996418223i
Since there are complex roots, the matrix is not diagonalizable.
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