Suppose T is invertible then show that (T-1)* = (T*)-1
Solution: Let u∈V.Since T is invertible and hence surjective,∴u=Tw for some vector w.If v∈V,<(T−1)∗v,Tw> = <v,T−1Tw> = <v,w>and <(T−1)∗v,Tw> = <T∗(T∗)−1v,w> = <v,w>Since for all u,v∈V,<(T−1)∗v,u>=<(T∗)−1v,u>∴ (T−1)∗=(T∗)−1Hence proved.Solution: ~Let~u\in V. Since~ T ~ is ~ invertible~ and ~ hence ~surjective, \\ \therefore u=Tw~for ~some~ vector ~w.\\ If ~ v \in V,< (T^{-1})^ * v,Tw>~=~<v,T^{-1}Tw>~=~<v,w> \\and~ < (T^{-1})^ * v,Tw>~=~<T^*(T^*)^{-1}v,w>~=~<v,w> \\Since ~ for ~all ~ u,v \in V, <(T^{-1})^ * v,u>=<(T^*)^{-1}v,u> \\ \therefore ~ (T^{-1})^ *=(T^*)^{-1} \\Hence ~ proved.Solution: Let u∈V.Since T is invertible and hence surjective,∴u=Tw for some vector w.If v∈V,<(T−1)∗v,Tw> = <v,T−1Tw> = <v,w>and <(T−1)∗v,Tw> = <T∗(T∗)−1v,w> = <v,w>Since for all u,v∈V,<(T−1)∗v,u>=<(T∗)−1v,u>∴ (T−1)∗=(T∗)−1Hence proved.
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