A semi-circle of radius 14 cm is formed from a piece of wire. If it is bent into a rectangle whose length is 1 cm more than its width, find the area of the rectangle.
Given that a semi circle of radius 14cm is formed from a piece of wire
Now, the perimeter of the semi circle is "r(\\pi+2)" where, r=radius and "\\pi=\\frac{22}{7}"
Now the perimeter "=14(\\frac{22}{7}+2)cm"
"=(14+28)cm"
"=72cm"
This is the perimeter of the rectangle
Let the width of the rectangle is x cm
therefore the length is 2cm more than its width
"=(x+2)cm"
Now the perimeter of rectangle is "2[(x+2)+x]cm"
Now in our problem
"2(2x+2)=72"
"2x+2=36"
"x+1=18"
"x=17"
The width of the rectangle is 17cm
The length of the rectangle is "x+2"
"=17+2=19"
therefore the length of the rectangle is 19cm
Now, the area of the rectangle is given by "L\\times W"
"=17\\times19"
"=323cm^2"
Area =323cm2
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