Question #270790

The vertices of a triangle are R (3,0), S (-1,3), and T (0, -2). a) Classify the triangle by side length and b) Find the perimeter of the triangle to the nearest tenth.


1
Expert's answer
2021-11-29T13:20:05-0500


a)


RS=(13)2+(30)2=5RS=\sqrt{(-1-3)^2+(3-0)^2}=5

RT=(03)2+(20)2=13RT=\sqrt{(0-3)^2+(-2-0)^2}=\sqrt{13}

TS=(10)2+(23)2=26TS=\sqrt{(-1-0)^2+(-2-3)^2}=\sqrt{26}

It is a versatile triangle.


b)


PRST=5+13+2613.7P_{RST}=5+\sqrt{13}+\sqrt{26}\approx13.7


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