Answer to Question #201825 in Geometry for tynasia

Question #201825

miguel finds the equation of a line that is perpendicular to y=ax+b

. If he multiplies the slopes of the two lines, what is the product?


1
Expert's answer
2021-06-03T12:20:56-0400

Slope of a line y=mx+c is m

Equation of a perpendicular line to the line ax+by+c =0

is bx-ay+k=0

Given the equation of a line is:-

y=ax+b

\therefore Slope of this line =a

Now,

y=ax +b

    \implies ax-y+b=0

\therefore General equation of a perpendicular line to ax-y+b=0 is ,

-x-ay+k=0

    \implies -ay=x-k

    y=1ax+ka\implies y=-\frac{1}{a}x+\frac{k}{a}

Slopeoftheperpendicularline=1a\therefore Slope of the perpendicular line =-\frac{1}{a}

Hence, the product of the slope =a(1a)a \cdot( \frac{-1}{a})

=-1


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