Ferris wheel cars are at a position of A (9,33) and B (27,-15). One of its axle is
represented by 3y+2x-7= 0 where it passes through the center of the wheel.
Draw the suitable graph of the said situation.
Solution
Let the center of the Ferris wheel to be (x, y)
therefore,
(x - 9)2 + (y - 33)2 = (x - 27)2 + (y - (-15))2
x2-18x+ 81+y2 - 66y + 1089 = x2 - 54x + 729 + y2 + 30y+225
it can be simplified to
36x - 96y= - 216 or
6x - 16y = -26 (eqn1)
Equation of the axle is given by;
3y + 2x = 7 (eqn2)
Solving the two equations simultaneously
(2x +3y = 7)*3
6x - 16y = -26
thus y= 57/25
replace y in (eqn2)
2x + 3( 57/25) = 7
x = 2/ 25
Thus the center of the Ferris wheel is given by ( 2/ 25, 57/25 )
Below is a graph illustrating the solution:
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