Ferris wheel cars are at a position of A (9,33) and B (27,-15). One of its axle is
represented by 3y+2x-7= 0 where it passes through the center of the wheel.
Draw the suitable graph of the said situation.
Let the center of the Ferris wheel to be (x, y)
therefore,
"(x - 9)^2 + (y - 33)^2 = (x - 27)^2 + (y - (-15))^2"
"x^2-18x+ 81+y^2 - 66y + 1089 = x^2 - 54x + 729 + y^2 + 30y+225"
it can be simplified to
"36x - 96y= - 216 \\newline\n\n6x - 16y = -26 ............. (eqn1)"
Equation of the axle is given by;
"3y + 2x = 7........... (eqn2)"
Solving the two equations simultaneously
"(2x +3y = 7)*3\\newline\n\n6x - 16y = -26"
thus y= 57/25
replace y in (eqn2)
"2x + 3( 57\/25) = 7\\newline\n\nx = 2\/ 25"
Thus the center of the Ferris wheel is given by ( 2/ 25, 57/25 )
Graph illustrating of the solution is attached.
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