Question #155198

Find the approximately the difference between the areas of two spheres whose radii are 4 feet and 4.05 feet.


1
Expert's answer
2021-01-19T04:36:04-0500

We have r1=4ftr_1=4ft and r2=4.05ftr_2=4.05ft

And total surface area of a sphere is

S=4πr2S=4\pi r^2

,where rr is the radius of the sphere.


So, difference between the two surface areas:-


S2S1=4πr224πr12=4π(r22r12)=4π((4.05)2(4)2)=4π(16.402516)=4π(0.4025)=43.140.4025=5.0554sqftS_2-S_1\\ =4\pi r_2^2-4\pi r_1^2\\ =4\pi(r_2^2-r_1^2)\\ =4\pi((4.05)^2-(4)^2)\\ =4\pi(16.4025-16)\\ =4\pi(0.4025)\\ =4\cdot3.14\cdot0.4025\\ =5.0554\>sq\>ft

So, the difference between the surface areas is 5.05545.0554 sq ft.


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