4. Given a=3 m,H=12 m
V=31a2HV=31(3 m)2(12 m)=36 m3 The volume of the water is 36 m3.
5.
Ha=H1a1=const Then
a1=a⋅HH1
a1=3 m⋅12 m7 m=1.75 m
S1=(a1)2=(1.75 m)2=3.0625 m2 The area at the surface of the water when it is 7m deep is 3.0625 m2.
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