We have h=15 m, V=125 m3.
1 . Let a be the base edge of this square pyramid.
Volume of the pyramid is V=31Bh , where B=a2 is area of base.
V=31a2h
a2=h3V
a=h3V=153×125=25=5
2.Let l be the slant height of the pyramid.
Then l=h2+(2a)2=152+2.52=925/4=537/2≈15.2 m
3.We can find the lateral area using formula L=21Pl , where P=4a is the perimeter of the base, l is the slight height.
L=24al=2×24×5×537=2537≈152 m2 .
Answer: 1. a=5 m , 2. l=537/2≈15.2 m , 3. L=2537≈152 m2 .
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