Question #213037

Show that a compact metric space X is locally compact.



1
Expert's answer
2021-07-05T15:32:27-0400

Let XX be a compact metric space, xXx\in X a point and xUx\in U an open neighbourhood of xx. As UU is open, there is a certain r>0r>0 such that the open ball B(x,r)UB(x,r)\subseteq U. Now by considering the closed ball F:=Bclosed(x,r/2)F:=B_{closed}(x,r/2) we have xFB(x,r)Ux\in F\subseteq B(x,r)\subseteq U. Finally, FF is closed and thus is compact, because XX is a compact metric space.


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