Question #206018

Show that a partially ordered M can have at most one element a such that a <=x for all x in M and at most one element b such that x<=b for all xin M. [If such an a (or b) exists, it is called the least element (greatest element, respectively) of M.]


1
Expert's answer
2021-07-19T14:23:17-0400

An element xMx\isin M is maximal (minimal) if there does not exist yM{x}y\isin M\setminus \{x\} with

xy (yx)x\preceq y\ (y\preceq x).

So, M can have at most one maximal element and one minimal element.


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