Question #198631

Find p-adic norm of |6|_3


Expert's answer

The p−p-adic norm of a rational number ab=pαa′b′\frac{a}{b}=p^\alpha\frac{a'}{b'} where p∤a′,b′p\nmid a', b' is given by p−αp^{-\alpha}. As 6=3×26=3\times 2 and 33 does not divide 22, we have ∣6∣3=3−1=1/3|6|_3=3^{-1}=1/3 .


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