Find p-adic norm of |6|_3
The p−p-p−adic norm of a rational number ab=pαa′b′\frac{a}{b}=p^\alpha\frac{a'}{b'}ba=pαb′a′ where p∤a′,b′p\nmid a', b'p∤a′,b′ is given by p−αp^{-\alpha}p−α. As 6=3×26=3\times 26=3×2 and 333 does not divide 222, we have ∣6∣3=3−1=1/3|6|_3=3^{-1}=1/3∣6∣3=3−1=1/3 .
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Find p-adic norm of |137|_2
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Dear smi, please use the panel for submitting a new question.
Find p-adic norm of |137|_2