Answer to Question #164576 in Functional Analysis for Ebenezer

Question #164576

Define f(x) = sinx on [0, 2pi]. Find two increasing functions h and g for which f = h — g on 

[0, 2pi]. 


1
Expert's answer
2021-02-24T07:41:04-0500

We will search the functions h,g:[0;2π]Rh,g:[0;2\pi]\to\mathbb{R} which are C1\mathcal{C}^1. We have f=(hg)=hgf'=(h-g)'=h'-g'. The functions h,gh,g are strictly increasing if h,g>0h', g'>0 on [0;2π][0;2\pi]. Thus we need to find two positive continuous functions h,gh',g' such that hg=cosxh'-g'=\cos x. For hh' we need to take something that is always strictly bigger than cosx\cos x, for example, h=2=consth'=2=const. In this case g=2cosxg'=2-\cos x. Both are always positive. Now by finding their primitives h=2x+C,g=2xsin(x)+Ch=2x+C, g=2x-\sin(x)+C, we see that the difference of such two functions is clearly sin(x)\sin(x) and they both are strictly increasing, as their derivatives are positive.


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