Question #98516
Use properties of Boolean algebra to simplify the following Boolean expression (show-
ing all the steps):
(x + y') (x + y')'
1
Expert's answer
2019-11-18T11:19:29-0500

Boolean expression


We need to simplify the given Boolean expression


Solution:


Some rules useful to simplify the Boolean expression



1). x+xˉ=12). x.xˉ= 03).x+y=xˉ.yˉ1). \space x + \bar {x} = 1 \\ 2).\space x . \bar {x} = \space 0 \\ 3). \overline {x + y} = \bar {x} . \bar {y}

Given,



(x+yˉ)(x+yˉ)=(x+yˉ)(xˉ.xˉˉ)( x + \bar {y} ) (\overline {x+ \bar {y}} ) = ( x + \bar {y} ) ( \bar x . \bar {\bar {x}})

=(x+yˉ)(xˉ.x)=(x+yˉ).0=0= ( x + \bar {y} ) ( \bar x . {x})= ( x + \bar {y}) . 0 = 0

Answer:

(x+yˉ)(x+yˉ)=(x + \bar {y} ) (\overline {x+ \bar {y}} ) = 0


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