Question #98476
Police report that 90% of drivers stopped on suspicion of drunk driving are given a
breath test, 11% are given a blood test, and 8% are given both.
(a) In this context, define two events A and B.
(b) Write the given information in probability notation.
(c) Explain, in this context, the meaning of P(A ∩ B).
(d) Are A and B disjoint events?
(e) Are A and B independent events?
1
Expert's answer
2019-11-12T10:13:35-0500

Probabilities of an Events

(a).


Event A = a drunk driving are given a breath test.


Event B = a drunk driving are given a blood test.


(b).


P(A) = 90% =90100=0.9\frac{90} {100} =0.9



P(B ) = 11% = 11100=0.11\frac {11} {100} = 0.11



P(Both) = P(AB)=8P(A\bigcap B ) = 8% = 8100=0.08\frac{8} {100} = 0.08


(c).


P(AB)=P(A\bigcap B ) = The probability that the drivers stopped on suspicion of drunk driving are given both

breath test AND blood test.

(d).

We knows, If the Events A and B are Disjoint, we can write as

P(AB)=0P(A\bigcap B) = 0

But, Here P(AB)=0.080P(A\bigcap B) = 0.08 \ne 0


So, the Events A and B are not disjoint


(e).


If the events A and B are independent, then P(AB)=P(A)×P(B)P(A\bigcap B) = P(A) \times P(B)



Here,

P(AB)=0.08 and P(A)×P(B)=0.9×0.11=0.099P(A\bigcap B ) = 0.08 \space and \space P(A) \times P(B) = 0.9 \times 0.11 = 0.099

So,

P(AB)P(A)×P(B)P(A\bigcap B) \ne P(A) \times P(B)

So, the events A and B are not Independent

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