Probabilities of an Events
(a).
Event A = a drunk driving are given a breath test.
Event B = a drunk driving are given a blood test.
(b).
P(A) = 90% =10090=0.9
P(B ) = 11% = 10011=0.11
P(Both) = P(A⋂B)=8% = 1008=0.08
(c).
P(A⋂B)= The probability that the drivers stopped on suspicion of drunk driving are given both
breath test AND blood test.
(d).
We knows, If the Events A and B are Disjoint, we can write as
P(A⋂B)=0
But, Here P(A⋂B)=0.08=0
So, the Events A and B are not disjoint
(e).
If the events A and B are independent, then P(A⋂B)=P(A)×P(B)
Here,
P(A⋂B)=0.08 and P(A)×P(B)=0.9×0.11=0.099 So,
P(A⋂B)=P(A)×P(B) So, the events A and B are not Independent
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