Question #98296
Use mathematical induction to prove that 4 is a factor of 9n − 5
n
for all integers n ≥ 1.
1
Expert's answer
2019-11-11T11:04:34-0500

Putting n=1

We get

95=49-5=4

Which is divisible by 4 so 4 is the factor of 4


Let

T(k)=9k5k=4m for some mT(k) =9k-5k=4m\ for \ some \ m is true     ....(1)\ \ \ \ ....(1)


For

T(k+1)T(k+1)

Now,


T(k+1)=9(k+1)5(k+1)T(k+1)= 9(k+1)-5(k+1)


=9k+95k5=4m+4=9k+9-5k-5=4m+4

=4(m+1)=4(m+1)

Thus, T(k+1)T(k+1) is divisible by 4, hence 4 is a factor of it. By the principle of mathematical induction, 4 is a factor of 9n-5n for all integers n1.n \geq 1.


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