Putting n=1
We get
9−5=4
Which is divisible by 4 so 4 is the factor of 4
Let
T(k)=9k−5k=4m for some m is true ....(1)
For
T(k+1)
Now,
T(k+1)=9(k+1)−5(k+1)
=9k+9−5k−5=4m+4
=4(m+1) Thus, T(k+1) is divisible by 4, hence 4 is a factor of it. By the principle of mathematical induction, 4 is a factor of 9n-5n for all integers n≥1.
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