Use a direct proof to show that the sum of two odd integers(k and l) is even.
Proof.
Let "k" and "l" be the odd integers. Then there exist some integers "k_0" and "l_0" such that
"k=2k_0+1,"
"l=2l_0+1."
We can find the sum:
"k+l=(2k_0+1)+(2l_0+1)=2k_0+2l_0+2=2(k_0+l_0+1),"
where "k_0+l_0+1" is an integer as a sum of integers.
So "k+l" is divisible by 2 and is even.
The proof is finished.
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