Answer to Question #331512 in Discrete Mathematics for Celes

Question

Suppose there are 19 Math majors, 17 English majors, and no double majors. How many ways

are there to choose someone who is either a Math major or a English major?

Answer 1

Since there are no double majors, we should simply add the number of Math majors and the number of English majors:

$19+17=36$

The answer is $36$