If A = {5,6,7} and B = {2,3}, {(2,6),(2,5),(3,7)} ⊆ B×A.
Consider the Cartesian product "B\\times A=\\{(2,5),(2,6),(2,7),(3,5),(3,6),(3,7)\\}". As we can see, the pairs "(2,6), (2,5)" and "(3,7)" belong to the set "B\\times A". Thus, "\\{(2,6), (2,5),(3,7)\\}\\sube B\\times A".
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