Question #316883

Five thousand lottery tickets are sold for $1 each. One ticket will win $1000, two tickets will win $500 each, and ten tickets will win $100 each. Let X denote the net gain from the purchase of a randomly selected ticket.

a. Construct the probability distribution of C

b. Compute the standard deviation of X


1
Expert's answer
2022-03-24T13:39:45-0400

Let X denote the net gain from the purchase of a randomly selected ticket.

For the first prize winner the net gain is 1000-1=999. So, P(X=999)=15000=0.0002P(X=999)=\frac{1}{5000}=0.0002

For second prize winner, P(X=499)=25000=0.0004P(X=499)=\frac{2}{5000}=0.0004

For third prize winner, P(X=99)=105000=0.002P(X=99)=\frac{10}{5000}=0.002

If you don't win any ticket then P(X=1)=1[P(X=999)+P(X=499)+P(X=99)]P(X=-1)=1-[P(X=999)+P(X=499)+P(X=99)]

=1[0.0002+0.0004+0.002]=0.9974=1-[0.0002+0.0004+0.002]=0.9974


a. Probability distribution




b. Standard deviation

E(X)=XP(X=x)=9990.0002+4990.0004+990.002+10.9974=0.4E(X)=∑X*P(X=x)=999*0.0002+499*0.0004+99*0.002+-1*0.9974=-0.4




σ=319.64=17.8785\sigma=\sqrt{319.64}=17.8785


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