Let A, B, and C be sets. Show that (A − B) − C =
(A − C) − (B − C).
(A−B)−C=(A∩Bˉ)−C=A∩Bˉ∩Cˉ(A−C)−(B−C)=(A∩Cˉ)−(B∩Cˉ)==(A∩Cˉ)∩B∩Cˉ‾=A∩Cˉ∩(Bˉ∪C)==(A∩Cˉ∩Bˉ)∪(A∩Cˉ∩C)=(A∩Cˉ∩Bˉ)∪∅=A∩Bˉ∩Cˉ\left( A-B \right) -C=\left( A\cap \bar{B} \right) -C=A\cap \bar{B}\cap \bar{C}\\\left( A-C \right) -\left( B-C \right) =\left( A\cap \bar{C} \right) -\left( B\cap \bar{C} \right) =\\=\left( A\cap \bar{C} \right) \cap \overline{B\cap \bar{C}}=A\cap \bar{C}\cap \left( \bar{B}\cup C \right) =\\=\left( A\cap \bar{C}\cap \bar{B} \right) \cup \left( A\cap \bar{C}\cap C \right) =\left( A\cap \bar{C}\cap \bar{B} \right) \cup \emptyset =A\cap \bar{B}\cap \bar{C}(A−B)−C=(A∩Bˉ)−C=A∩Bˉ∩Cˉ(A−C)−(B−C)=(A∩Cˉ)−(B∩Cˉ)==(A∩Cˉ)∩B∩Cˉ=A∩Cˉ∩(Bˉ∪C)==(A∩Cˉ∩Bˉ)∪(A∩Cˉ∩C)=(A∩Cˉ∩Bˉ)∪∅=A∩Bˉ∩Cˉ
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