Answer to Question #253241 in Discrete Mathematics for Anshul

Question #253241

Find out reflexive, symmetric and transitive closure of following relation R. 

R = {(1,2), (2,3), (3,3)}


1
Expert's answer
2021-10-19T16:29:02-0400

Let A={1,2,3}

For R to be reflexive, then it aRa for all a in A. But, 2 22\not R~ 2. Hence R is not reflexive.

For R to be symmetric, then aRb    bRaa,bAaRb\implies bRa \forall a,b\in A. But 1R2 but 211R2 \text{ but } 2\not R 1Hence R is not symmetric.

For R to be transitive, then aRb and bRc, then aRc.aRb \text{ and } bRc, \text{ then }aRc. But, 1R2 and 2R3 and 131\not R 3. Hence R is not transitive.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment