It follows that ∣A∣={2, ∣B∣=31, ∣B∣=3. Suppose that ∣A∣=1, then B={1,1,∣B∣}={1,∣B∣}, and we have a contradiction with ∣B∣=3. Therefore, ∣A∣=2, and thus ∣B∣=3. Taking into account that B={1,∣A∣,∣B∣}={1,2,∣B∣} and ∣B∣<3, we conclude that ∣B∣=2.
Consequently, A={3,2} and B={1,2}.
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