¬(p∧¬q)∨r≡[(¬p)∨(¬(¬q))]∨r≡[(¬p)∨q]∨r≡(¬p)∨(q∨r)≡p→(q∨r)≡(p∨q)→r\neg(p \land \neg q) \lor r\\ \equiv [(\neg p) \lor (\neg( \neg q))] \lor r\\ \equiv [(\neg p) \lor q] \lor r\\ \equiv (\neg p) \lor (q \lor r)\\ \equiv p \to (q \lor r)\\ \equiv (p \lor q) → r¬(p∧¬q)∨r≡[(¬p)∨(¬(¬q))]∨r≡[(¬p)∨q]∨r≡(¬p)∨(q∨r)≡p→(q∨r)≡(p∨q)→r
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment