Prove the following sentences using any prove method [ the most appropriate one]:
a) If r is rational and s is irrational, prove that 2r+s is irrational.
b) If t and s are integers and t × s is even, then t is even or s is even.
Solution:
(a):
Suppose r is rational and s is irrational. Assume for contradiction that r + 2s is rational. Then there are integers a and b with b "\\ne" 0 such that r + 2s = "\\frac ab" . Since r is rational, there are integers c and d such that r ="\\frac cd" . Then 2s = "\\frac ab-\\frac cd" = "\\frac{ad\u2212bc}{bd}" is rational, contradicting the fact that 2s is irrational.
Hence, proved.
(b):
Given that t and s are integers and t × s is even.
So, t × s = 2m, for some constant m.
"\\dfrac{t \u00d7 s }2=m\n\\\\\\Rightarrow \\dfrac{t }2\u00d7 s=m \\ or\\ \\dfrac{s }2\u00d7 t=m"
"\\Rightarrow" Either t is divisible by 2, so it is even
or s is divisible by 2, so it is even.
Hence, proved.
Comments
Leave a comment