Question #225253

Let A= {0, 1, 2, 3} and define relations R, S and T on A as follows:
R= { (0,0),(0,1),(0,3),(1,0),(1,1),(2,2),(3,0),(3,3)}
S= {(0, 0),(2,2),(1,1), (0, 2), (0, 3), (2, 3),(2,2)}
T= {(0, 1), (2, 3),(0,0),(2,2),(1,0),(3,3),(3,2)}
i. Is R Reflexive? Symmetric? AntiSymmetric?
ii. Is S Reflexive? Symmetric? AntiSymmetric?
iii. Is T Reflexive? Symmetric? AntiSymmetric?

Expert's answer

Solution:

Given, A= {0, 1, 2, 3}

R= { (0,0),(0,1),(0,3),(1,0),(1,1),(2,2),(3,0),(3,3)}

S= {(0, 0),(2,2),(1,1), (0, 2), (0, 3), (2, 3),(2,2)}

T= {(0, 1), (2, 3),(0,0),(2,2),(1,0),(3,3),(3,2)}

Reflexive: (a,a)∈R∀a∈A(a,a)\in R\forall a\in A

Symmetric: (a,b)∈R⇒(b,a)∈R,∀a,b∈A(a,b)\in R\Rightarrow (b,a)\in R, \forall a,b\in A

Anti-Symmetric: (a,b)∈R,(b,a)∈R,⇒a=b,∀a,b∈A(a,b)\in R,(b,a)\in R,\Rightarrow a=b, \forall a,b\in A

(i) Using these definitions, R is reflexive, symmetric but not anti-symmetric as (0,3),(3,0)∈R\in R but 0≠30\ne3

(ii) S is not reflexive as (3,3) is not in S.

S is symmetric and anti-symmetric.

(iii) T is not reflexive as (1,1) is not in T.

T is symmetric.

But T is not anti-symmetric as (0,1),(1,0) ∈T\in T but 1≠01\ne 0


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