Answer to Question #213807 in Discrete Mathematics for zami

Question #213807

An examination paper consists of 5 questions in section A and 5 questions in section B. A total of 8 questions must be answered. In how many ways can a student select the questions if he is to answer at least 4 questions from section A.


1
Expert's answer
2021-07-06T03:40:48-0400

Student has to solve at least 44 questions from section A.

So, he can choose in 2 ways :

a)a) 44 from section A and 44 from section B.

b)b) 55 from section A and 33 from section B.

Total number of ways of selecting the questions N=N= Na+NbN_a+N_b

 N=5C4×5C4+5C5×5C3\ N=^5C_4\times ^5C_4 + ^5C_5\times ^5C_3

N=5!(54)!(4!)×5!(54)!(4!)+5!(55)!(5!)×5!(53)!(3!)N=\frac{5!}{(5-4)!(4!)}\times \frac{5!}{(5-4)!(4!)}+\frac{5!}{(5-5)!(5!)}\times \frac{5!}{(5-3)!(3!)}

N=5!1!4!5!1!4!+5!0!5!5!2!3!=5×5+1×10N=\frac{5!}{1!4!}\frac{5!}{1!4!}+\frac{5!}{0!5!}\frac{5!}{2!3!}=5\times 5+ 1\times 10

N=25+10=35N=25+10=35


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