Question #203028

There were 100 students in the library who responded to how they completed their research paper. • 18 students only used the periodicals. • 29 students used the web and books. • 15 students used books, the web, and periodicals. • 40 students used books and periodicals. • 20 used the web and periodicals. • 60 students used books. • 7 students did not use the web, nor books, nor the periodicals. a) Represent this information with a Venn diagram. (8 marks) b) How many students only used the web in their research? (2 marks) c) How many students used books or periodicals?


Expert's answer

a)


N(P∩B′∩W′)=18N(P\cap B'\cap W')=18

N(B∩W)=29N(B\cap W)=29

N(B∩W∩P)=15N(B\cap W\cap P)=15

N(B∩W∩P′)=N(B∩W)−N(B∩W∩P)N(B\cap W\cap P')=N(B\cap W)-N(B\cap W\cap P)

=29−15=14=29-15=14




N(B∩P)=40N(B\cap P)=40

N(B∩P∩W′)=N(B∩P)−N(B∩P∩W)N(B\cap P\cap W')=N(B\cap P)-N(B\cap P\cap W)

=40−15=25=40-15=25

N(W∩P)=20N(W\cap P)=20

N(W∩P∩B′)=N(W∩P)−N(B∩P∩W)N(W\cap P\cap B')=N(W\cap P)-N(B\cap P\cap W)

20−15=520-15=5

N(B)=60N(B)=60

N(B∩P′∩W′)=N(B)−N(B∩W)−N(B∩P)N(B\cap P'\cap W')=N(B)-N(B\cap W)-N(B\cap P)

+N(B∩W∩P)=60−29−40+15=6+N(B\cap W\cap P)=60-29-40+15=6

N(B′∩W′∩P′)=7N(B'\cap W' \cap P')=7

N(W∩B′∩P′)=100−N(B′∩W′∩P′)N(W\cap B'\cap P')=100-N(B'\cap W' \cap P')

−N(P∩B′∩W′)−N(W∩P∩B′)-N(P\cap B'\cap W')-N(W\cap P\cap B')

=100−7−60−18−5=10=100-7-60-18-5=10


b)


N(W∩B′∩P′)=10N(W\cap B'\cap P')=10

c)


N(B∪P)=N(B∩W′∩P′)+N(P∩B′∩W′)N(B\cup P)=N(B\cap W'\cap P')+N(P\cap B'\cap W')

+N(B∩P)=6+18+40=64+N(B\cap P)=6+18+40=64


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