Answer to Question #201750 in Discrete Mathematics for syasya

Question

given that the function f(x) = 4x + 1 , find a formula for f^-1(x)

Answer 1

Solution:

$f(x)=y=4x+1 \\\Rightarrow y-1=4x \\\Rightarrow \dfrac{y-1}4=x \\\therefore f^{-1}(x)=\dfrac{x-1}4$