given that the function f(x) = 4x + 1 , find a formula for f-1(x)
Solution:
"f(x)=y=4x+1\n\\\\\\Rightarrow y-1=4x\n\\\\\\Rightarrow \\dfrac{y-1}4=x\n\\\\\\therefore f^{-1}(x)=\\dfrac{x-1}4"
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