1*1=1 is not divisible by 4, therefore (1,1)∈/R
1*2=2*1=2 is not divisible by 4, therefore (1,2),(2,1)∈/R
1*3=3*1=3 is not divisible by 4, therefore (1,3),(3,1)∈/R
1*4=4*1=4 is divisible by 4, therefore (1,4),(4,1)∈R
1*5=5*1=5 is not divisible by 4, therefore (1,5),(5,1)∈/R
1*6=6*1=6 is not divisible by 4, therefore (1,6),(6,1)∈/R
1*7=7*1=7 is not divisible by 4, therefore (1,7),(7,1)∈/R
Continuing the reasoning in a similar way, we get the elements of the relation R:
R={(1,4),(4,1),(2,2),(2,4),(4,2),(2,6),(6,2),(3,4),(4,3),(4,4),
(4,5),(4,6),(4,7),(5,4),(6,4),(7,4),(6,6)}
Find the inverse relation:
R−1={(y,x)∣(x,y)∈R}={(4,1),(1,4),(2,2),(4,2),(2,4),(6,2),(2,6),(4,3),(3,4),(4,4),(5,4),
(6,4),(7,4),(4,5),(4,6),(4,7),(6,6)}
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