Question #185249

Give a contrapositive proof of the theorem; "If n is an interfer and 3n + 2 is even, then n is even."?


1
Expert's answer
2021-05-06T15:02:30-0400

Let us give a contrapositive proof of the theorem: "If nn is an interger and 3n+23n + 2 is even, then nn is even.".

For this suppose that nn is an interger and 3n+23n + 2 is even, but nn is not even, and hence nn is odd. Then n=2k+1n=2k+1 for some kZ.k\in\mathbb Z. It follows that 3n+2=3(2k+1)+2=6k+3+2=(6k+4)+1=2(3k+2)+13n+2=3(2k+1)+2=6k+3+2=(6k+4)+1=2(3k+2)+1, where 3k+23k+2 is integer. Therefore, 3n+23n+2 is odd. We conclude that 3n+23n+2 is not even, that is we have a contradiction with initial assumption that 3n+23n + 2 is even.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS