Question #184783

Use the truth table to transform each of the following wffs into the full conjunctive normal form

(P→Q)→P. P→(Q→P)

(P∨Q)∧R. P→Q∧R. Q∧¬P→P



Expert's answer

a. (P→Q)→P = P


b. P→(Q→P) = 1



c. (P∨Q)∧R



d. P→Q∧R = (Q ∧ R) ∨ ¬P


e. Q∧¬P→P = P ∨ ¬Q

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