Use the truth table to transform each of the following wffs into the full conjunctive normal form
(P→Q)→P. P→(Q→P)
(P∨Q)∧R. P→Q∧R. Q∧¬P→P
a. (P→Q)→P = P
b. P→(Q→P) = 1
c. (P∨Q)∧R
d. P→Q∧R = (Q ∧ R) ∨ ¬P
e. Q∧¬P→P = P ∨ ¬Q
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